目录初三上学期化学六个方程式 九年级上所有化学方程式公式 九年级上册30个化学方程式 初中九上化学所有化学方程式 九上化学第四单元化学方程式
涔濆勾绾у寲瀛︿笂鍐屽寲瀛︽柟绋嬪紡锛�
F2+H2=2HF
2F2+2H2O=4HF+O2
Cl2+2FeCl2=2FeCl3
2Cl2+2NaBr=2NaCl+Br2
Cl2+2NaI=2NaCl+I2
Cl2+SO2+2H2O=H2SO4+2HCl
S+6HNO3(娴�)=H2SO4+6NO2鈫�+2H2O
3S+4HNO3(绋�)=3SO2+4NO鈫戠寽鐩�娌�+2H2O
PX3+X2=PX5
C+CO2=2CO
Si+2NaOH+H2O=Na2SiO3+2H2鈫�
Cl2+H2O=HCl+HClO
Cl2+2NaOH=NaCl+NaClO+H2O
2Cl2+2Ca(OH)2=CaCl2+Ca(ClO)2+2H2O
4Na+O2=2Na2O
2Na+S=Na2S
2Na+2H2O=2NaOH+H2鈫�
Mg+H2SO4=MgSO4+H2鈫�
2Al+6HCl=2AlCl3+3H2鈫�
2Al+3H2SO4=Al2(SO4)3+3H2鈫戠�楃撼
2Al+6H2SO4(娴撱�佺儹)=Al2(SO4)3+3SO2鈫�+6H2O
Al+4HNO3(绋�)=Al(NO3)3+NO鈫�+2H2O
2Al+2NaOH+2H2O=2NaAlO2+3H2鈫�
Fe+2HCl=FeCl2+H2鈫�
Fe+CuCl2=FeCl2+Cu
16HCl+2KMnO4==2KCl+2MnCl2+5Cl2鈫�+8H2O
2H2S+SO2=3S鈫�+2H2O
2NH3+3Cl2=N2+6HCl
8NH3+3Cl2=N2+6NH4Cl
4NH3+3O2(绾�鍒欑僵姘�)=2N2+6H2O
4NH3+6NO=5N2+6H2O
4HF+SiO2=SiF4+2H2O
H2S+CuCl2=CuS鈫�+2HCl
H2S+FeCl2=(涓嶅弽搴�)
NH3+HCl=NH4Cl
NH3+HNO3=NH4NO3
2NH3+H2SO4=(NH4)2SO4
NH3+NaCl+H2O+CO2=NaHCO3+NH4Cl
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銆�銆�澶氱粌锛屾寚缁冪殑鏁伴噺鑰岃█锛涚簿缁冿紝鎸囩粌鐨勮川閲忚�岃█锛岀粌鐨勯�樼洰瑕佺簿閫夛紝瑕佹湁鎴愭晥锛屽仛杩囩殑棰樿�佺湡姝ｅ紕鎳傦紝缁冪殑鍐呭�归�愭�ユ墿灞曞拰娣卞寲锛屽湪灞傛�′笂閫愭�ユ彁楂橈紱宸х粌锛屽氨鏄�瑕佺粌涔犱粠涓嶅悓瑙掑害瑙ｉ�橈紝瀛︿細鐭ヨ瘑杩佺Щ锛屼妇涓�鍙嶄笁銆傞噰鐢ㄩ�樻捣鎴樻湳鏄�娌℃湁鏁堟灉鐨勶紝鍥犱负棰樼洰鐨勫彲鍙樻�у緢澶э紝涓嶅彲鑳界寽鍒伴�橈紝鍘嬪埌棰樸��
涓�銆佺噧鐑у弽搴�(鎻忚堪鐜拌薄瑕佺偣锛氬厜鎴栫伀鐒帮紝鏀剧儹锛岀敓鎴愮墿鐨勯�滆壊銆佺姸銆佹�佹皵鍛�)
1銆佺⒊鍏呭垎鐕冪儳锛�
C+O2=鐐圭噧CO2(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
(绌烘皵涓�锛氱孩鐑�)
(姘ф皵涓�锛氬彂鍑虹櫧鍏夛紝鏀惧嚭鐑�閲忥紝浜х敓浣跨煶鐏版按鍙樻祽娴婄殑鏃犺壊姘斾綋)
2銆佺⒊涓嶅厖鍒嗙噧鐑э細
2C+O2=鐐圭噧2CO(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
3銆佺～鐕冪儳锛�
S+O2=鐐圭噧SO2(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
(绌烘皵涓�锛氭贰钃濊壊鐏�鐒帮紝鏀惧嚭棣栧療娑茬儹閲忥紝浜х敓鍏锋湁鍒烘縺姘斿懗鐨勬皵浣�)
(姘ф皵涓�锛氳摑绱�鑹茬伀鐒帮紝鏀惧嚭鐑�閲忥紝浜х敓鍏锋湁鍒烘縺姘斿懗鐨勬皵浣�)
4銆佺７鐕冪儳锛�
4P+5O2=鐐圭噧P2O5(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
(浜х敓澶ч噺鐧界儫锛孭2O5姹℃煋绌烘皵)
5銆侀搧鐕冪儳锛�
3Fe+2O2=鐐圭噧Fe3O4(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
(姘ф皵涓�锛氬墽鐑堢噧鐑э紝鐏�鏄熷洓灏勶紝鏀惧嚭澶ч噺鐑�锛岀敓鎴愰粦鑹插浐浣�)
(鐡跺簳鐣欏皯閲忔按鎴栫粏娌欙紝闃叉�㈡簠钀界殑楂樻俯鐔斿寲鐗╃偢瑁傜摱搴曘��)
6銆侀晛鐕冪儳锛�
2Mg+O2=鐐圭噧2MgO(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
(鍙戝嚭鑰�鐪肩殑鐧藉厜锛岀敓鎴愮櫧鑹插浐浣�)
7銆佹阿姘旂噧鐑э細2H2+O2=鐐圭噧2H2O(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
(浜х敓娣¤摑鑹茬伀鐒帮紝骞插喎鐑ф澂澹佹湁灏忔按鏍�)
8銆佷竴姘у寲纰崇噧鐑э細
2CO+O2=鐐圭噧2CO2(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
(浜х敓钃濊壊鐏�鐒帮紝浜х敓浣跨煶鐏版按鍙樻祽娴婄殑鏃犺壊姘斾綋)
9銆佺敳鐑风噧鐑э細
CH4+2O2=鐐圭噧CO2+2H2O
(浜х敓鏄庝寒鐨勮摑鑹茬伀鐒�)
10銆佷箼閱囩噧鐑э細
C2H5OH+3O2=鐐圭噧2CO2+3H2O
浜屻�佸父瑙佹皵浣撳埗澶囨柟绋嬪紡
(涓�)鍒跺彇姘ф皵
1銆佽繃姘у寲姘�涓庝簩姘у寲閿版贩鍚堝埗姘ф皵锛�
2H2O2=MnO22H2O+O2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氬垎瑙ｅ弽搴�)
2銆佸姞鐑�姘�閰搁捑鍜屼簩姘у寲閿板埗澶囨哀姘旓細
2KClO3=MnO22KCl+O2#(鍩烘湰鍙嶅簲绫诲瀷锛氬垎瑙ｅ弽搴�)
3銆佸姞鐑�楂橀敯閰搁捑锛�
2KMnO4=鍔犵儹K2MnO4+MnO2+O2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氬垎瑙ｅ弽搴�)
(妫夎姳锛氶槻姝㈤珮閿伴吀閽剧矇鏈�鍫靛�炲�肩��)
(鍏堟挙瀵肩�″悗鐏�閰掔簿鐏�锛氶槻姝㈡按鍊掓祦鍥炶瘯绠″簳閮ㄨ�岀偢瑁傝瘯绠�)
4銆佸姞鐑�姘у寲姹烇細
2HgO=鍔犵儹2Hg+O2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氬垎瑙ｅ弽搴�)
5銆佺數瑙ｆ按锛�
2H2O=閫氱數H2鈫�+O2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氬垎瑙ｅ弽搴�)
(鐢垫瀬锛氭�ｆ哀璐熸阿;浣撶Н姣旓細姘�浜屾哀涓�;璐ㄩ噺姣旓細姘у叓姘�涓�;鍔犲叆纭�閰告垨姘㈡哀鍖栭挔鐨勭洰鐨勶細澧炲己姘寸殑瀵肩數鎬�)
(浜�)鍒跺彇浜屾哀鍖栫⒊
1銆佺煶鐏扮煶璺熺█鐩愰吀鍙嶅簲鍒朵簩姘у寲纰筹細
CaCO3+2HCl=CaCl2+H2O+CO2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氬�嶅垎瑙ｅ弽搴�)
2銆佺⒊閰镐笉绋冲畾锛�
H2CO3=H2O+CO2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氬垎瑙ｅ弽搴�)
3銆侀珮娓╃厖鐑х煶鐏扮煶锛�
CaCO3=楂樻俯CaO+CO2鈫�(CO2宸ヤ笟鍒舵硶锛屽熀鏈�鍙嶅簲绫诲瀷锛氬垎鑰呯墿瑙ｅ弽搴�)
(涓�)鍒跺彇姘㈡皵
1銆侀攲璺熺█纭�閰稿弽搴旓細
Zn+H2SO4=ZnSO4+H2鈫�
(瀹為獙瀹ゅ埗姘㈡皵锛屽熀鏈�鍙嶅簲绫诲瀷锛氱疆鎹㈠弽搴�)
2銆侀攲璺熺█鐩愰吀锛�
Zn+2HCl=ZnCl2+H2鈫�
(瀹為獙瀹ゅ埗姘㈡皵锛屽熀鏈�鍙嶅簲绫诲瀷锛氱疆鎹㈠弽搴�)
3銆侀晛璺熺█鐩愰吀鍙嶅簲锛�
Mg+2HCl=MgCl2+H2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氱疆鎹㈠弽搴�)
涓夈�佸叾浠栨柟绋嬪紡
1銆佷簩姘у寲纰充娇婢勬竻鐭崇伆姘村彉娴戞祳(CO2鐨勬��楠�)锛�
Ca(OH)2+CO2=CaCO3鈫�+H2O
2銆佷簩姘у寲纰虫憾浜庢按锛�
CO2+H2O=H2CO3(鍩烘湰鍙嶅簲绫诲瀷锛氬寲鍚堝弽搴�)
(CO2閫氬叆绱�鑹茬煶钑婅瘯娑诧紝璇曟恫鐢辩传鑹插彉涓虹孩鑹�)
3銆佹湪鐐�绮夎窡姘у寲閾滈珮娓╁叡鐑�锛�
C+2CuO=楂樻俯2Cu+CO2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氱疆鎹㈠弽搴�)
(榛戣壊绮夋湯閫愭笎鍙樼孩锛岀敓鎴愯兘浣挎緞娓呯煶鐏版按鍙樻祽娴婄殑姘斾綋)
4銆佹湪鐐�绮夎繕鍘熸哀鍖栭搧锛�
3C+2Fe2O3=楂樻俯4Fe+3CO2鈫�(鍩烘湰鍙嶅簲绫诲瀷锛氱疆鎹㈠弽搴�)
5銆佷竴姘у寲纰宠繕鍘熸哀鍖栭摐锛�
CO+CuO=鍔犵儹Cu+CO2(瑕佹湁灏炬皵澶勭悊瑁呯疆)
6銆丠2杩樺師姘у寲閾滐細H2+CuO=鍔犵儹Cu+H2O(鍩烘湰鍙嶅簲绫诲瀷锛氱疆鎹㈠弽搴�)
(鍙嶅簲鍓嶅厛閫氫竴娈垫椂闂存皵浣擄細鎺掑敖瑁呯疆涓�鐨勭┖姘旀垨姘ф皵;鍙嶅簲缁撴潫鍚庣户缁�閫氫竴娈垫椂闂存皵浣擄紝鐩磋嚦璇曞嵎鍐峰嵈鑷冲父娓╀笅锛氶槻姝㈢敓鎴愮殑Cu閲嶆柊琚�姘у寲鎴愭哀鍖栭摐)
7銆佷竴姘у寲纰宠繕鍘熸哀鍖栭搧(璧ら搧鐭跨偧閾�)锛�
3CO+Fe2O3=楂樻俯2Fe+3CO2
8銆佷竴姘у寲纰宠繕鍘熷洓姘у寲涓夐搧(纾侀搧鐭跨偧閾�)锛�
4CO+Fe3O4=楂樻俯3Fe+4CO2
鍥涖�侀噾灞炰笌鐩愭憾娑插弽搴�(鍩烘湰鍙嶅簲绫诲瀷锛氱疆娌″療鎹㈠弽搴�)
1銆侀搧涓庣～閰搁摐婧舵恫锛欶e+CuSO4=Cu+FeSO4
(婀挎硶鍐堕摐锛屼笉鑳界敤閾佹《鐩涙斁纭�閰搁摐婧舵恫鍘熺悊銆�)
2銆侀摑涓庣～閰搁摐婧舵恫锛�2Al+3CuSO4=Al2(SO4)3+3Cu
(婧舵恫鐢辫摑鑹查�愭笎鍙樻棤鑹诧紝鍥轰綋琛ㄩ潰鏈夌孩鑹茬墿璐ㄧ敓鎴�)
3銆侀攲涓庣～閰搁摐婧舵恫锛歓n+CuSO4=Cu+ZnSO4
(婧舵恫鐢辫摑鑹查�愭笎鍙樻棤鑹诧紝鍥轰綋琛ㄩ潰鏈夌孩鑹茬墿璐ㄧ敓鎴�)
4銆侀搧涓庣�濋吀閾舵憾娑诧細Fe+2AgNO3=Fe(NO3)2+2Ag
(婧舵恫鐢辨棤鑹查�愭笎鍙樻祬缁胯壊锛屽浐浣撹〃闈㈡湁閾剁櫧鑹茬墿璐ㄧ敓鎴�)
5銆侀摐涓庣�濋吀閾舵憾娑诧細Cu+2AgNO3=Cu(NO3)2+2Ag
(婧舵恫鐢辨棤鑹查�愭笎鍙樿摑鑹诧紝鍥轰綋琛ㄩ潰鏈夐摱鐧借壊鐗╄川鐢熸垚)
6銆侀攲涓庣�濋吀閾舵憾娑诧細Zn+2AgNO3=Zn(NO3)2+2Ag
(鍥轰綋琛ㄩ潰鏈夐摱鐧借壊鑹茬墿璐ㄧ敓鎴�)
鍒濅腑鍖栧�︾煡璇嗘�荤粨(
)
涓�銆�
1銆侀晛鍦ㄧ┖姘斾腑鐕冪儳锛�2Mg + O2 鐐圭噧 2MgO
鐜拌薄锛氾紙1锛夊彂鍑鸿��鐪肩殑鐧藉厜锛�2锛夋斁鍑虹儹閲忥紙3锛夌敓鎴愮櫧鑹茬矇鏈�
2銆侀搧鍦ㄦ哀姘斾腑鐕冪儳锛�3Fe + 2O2 鐐圭噧 Fe3O4
鐜拌薄锛氾紙1锛夊墽鐑堢噧鐑э紝鐏�鏄熷洓灏勶紙2锛夋斁鍑虹儹閲忥紙3锛夌敓鎴愪竴绉嶉粦鑹插浐浣�
娉ㄦ剰锛氱摱灞辨�樺簡搴曡�佹斁灏戦噺姘存垨缁嗘矙锛岄槻姝㈢敓鎴愮殑鍥轰綋鐗╄川婧呰惤涓嬫潵锛岀偢瑁傜摱搴曘��
4銆侀摐鍦ㄧ┖姘斾腑鍙楃儹锛�2Cu + O2 鈻� 2CuO鐜拌薄锛氶摐涓濆彉榛戙��
6銆侀摑鍦ㄧ┖姘斾腑鐕冪儳锛�4Al + 3O2 鐐圭噧 2Al2O3
鐜拌薄锛氬彂鍑鸿��鐪肩殑鐧藉厜锛屾斁鐑�锛屾湁鐧借壊鍥轰綋鐢熸垚銆�
7銆佹阿浼嶇�呮皵涓�绌烘皵涓�鐕冪儳锛�2H2 + O2 鐐圭噧 2H2O
鐜拌薄锛氾紙1锛変骇鐢熸贰
锛�2锛夋斁鍑虹儹閲忥紙3锛�
鍐呭�佸嚭鐜版按闆俱��
8銆佺孩锛堢櫧锛夌７鍦ㄧ┖姘斾腑鐕冪儳锛�4P + 5O2 鐐圭噧 2P2O5
鐜拌薄锛氾紙1锛夊彂鍑虹櫧鍏夛紙2锛夋斁鍑虹儹閲忥紙3锛夌敓鎴愬ぇ閲忕櫧鐑熴��
9銆佺～绮夊湪绌烘皵涓�鐕冪儳锛� S + O2 鐐圭噧 SO2鐜拌薄锛欰銆佸湪绾�鐨勬哀姘斾腑
鍙戝嚭鏄庝寒鐨勮摑绱�鐏�鐒帮紝鏀惧嚭鐑�閲忥紝鐢熸垚涓�绉嶆湁鍒烘縺鎬ф皵鍛崇殑姘斾綋銆�
B銆佸湪绌烘皵涓�鐕冪儳
锛�1锛夊彂鍑烘贰
锛�2锛夋斁鍑虹儹閲忥紙3锛夌敓鎴愪竴绉嶆湁鍒烘縺鎬ф皵鍛崇殑姘斾綋銆�
10銆佺⒊鍦ㄦ哀姘斾腑鍏呭垎鐕冪儳锛欳 + O2 鐐圭噧 CO2
鐜拌薄锛氾紙1锛夊彂鍑虹櫧鍏夛紙2锛夋斁鍑虹儹閲忥紙3锛�
鍙樻祽娴�
11銆佺⒊鍦ㄦ哀姘斾腑涓嶅厖鍒嗙噧鐑э細2C + O2 鐐圭噧 2CO
12銆佷簩姘у寲纰抽�氳繃鐏肩儹纰冲眰锛� C + CO2 楂樻俯 2CO锛堟槸鍚哥儹鐨勫弽搴旓級
13銆�
鍦ㄦ哀姘斾腑鐕冪儳锛�2CO + O2 鐐圭噧 2CO2
鐜拌薄锛氬彂鍑鸿摑鑹茬殑鐏�鐒帮紝鏀剧儹锛�
鍙樻祽娴娿��
14銆佷簩姘у寲纰冲拰姘村弽搴旓紙浜屾哀鍖栫⒊閫氬叆
锛夛細
CO2 + H2O === H2CO3 鐜拌薄锛�
鐢辩传鑹插彉鎴愮孩鑹层��
娉ㄦ剰锛�
锛嬫按鈫掗吀
濡傦細SO2 + H2O === H2SO3 SO3 + H2O === H2SO4
15銆�
婧朵簬姘达細CaO + H2O === Ca(OH)2锛堟�ゅ弽搴旀斁鍑虹儹閲忥級
娉ㄦ剰锛�
锛嬫按鈫掔⒈
婧朵簬姘达細Na2O + H2O 锛�2NaOH
婧朵簬姘达細K2O + H2O锛�2KOH
婧朵簬姘达細BaO + H2O ==== Ba锛圤H锛�2
16銆侀挔鍦ㄦ隘姘斾腑鐕冪儳锛�2Na + Cl2鐐圭噧 2NaCl
17銆�
浣�
锛欳uSO4 + 5H2O ==== CuSO4•5H2O
浜屻��
锛�
17銆佹按鍦�
鐨勪綔鐢ㄤ笅鍒嗚В锛�2H2O 閫氱數 2H2鈫�+ O2 鈫�
鐜拌薄锛氾紙1锛夌數鏋佷笂鏈夋皵娉′骇鐢熴�侶2锛歄2锛�2锛�1
姝ｆ瀬浜х敓鐨勬皵浣撹兘浣垮甫鐏�鏄熺殑鏈ㄦ潯澶嶇噧銆�
璐熸瀬浜х敓鐨勬皵浣撹兘鍦ㄧ┖姘斾腑鐕冪儳锛屼骇鐢熸贰
18銆佸姞鐑�
锛欳u2(OH)2CO3 鈻� 2CuO + H2O + CO2鈫�
鐜拌薄锛氱豢鑹茬矇鏈�鍙樻垚榛戣壊锛岃瘯绠″唴澹佹湁姘寸彔鐢熸垚锛�
鍙樻祽娴娿��
19銆佸姞鐑�
锛堟湁灏戦噺鐨�
锛夛細2KClO3 MnO2 2KCl + 3O2 鈫�
20銆佸姞鐑�
锛�2KMnO4 鈻矺2MnO4 + MnO2 + O2鈫�
21銆佸疄楠屽�ょ敤
鍒舵哀姘旓細2H2O2 MnO2 2H2O+ O2鈫�
鐜拌薄锛氭湁姘旀场浜х敓锛屽甫鐏�鏄熺殑鏈ㄦ潯澶嶇噧銆�
22銆佸姞鐑�
锛�2HgO 2Hg + O2鈫�
23銆侀敾鐑�
锛欳aCO3 CaO+CO2鈫戯紙浜屾哀鍖栫⒊宸ヤ笟鍒舵硶锛�
24銆佺⒊閰镐笉绋冲畾鑰屽垎瑙ｏ細H2CO3 === H2O + CO2鈫�
鐜拌薄锛�
鐢辩孩鑹插彉鎴愮传鑹层��
25銆�
鍙�
锛欳uSO4•5H2O 鍔犵儹 CuSO4 + 5H2O
涓夈��
锛�
锛�1锛夐噾灞炲崟璐� + 閰� -------- 鐩� + 姘㈡皵 锛�
锛�
26銆侀攲鍜�
鍙嶅簲锛歓n + H2SO4 === ZnSO4 + H2鈫�
27銆侀晛鍜�
鍙嶅簲锛歁g + H2SO4 === MgSO4 + H2鈫�
28銆侀摑鍜�
鍙嶅簲锛�2Al + 3H2SO4 === Al2(SO4)3 + 3H2鈫�
29銆侀攲鍜�
鍙嶅簲锛歓n + 2HCl === ZnCl2 + H2鈫�
30銆侀晛鍜�
鍙嶅簲锛歁g+ 2HCl === MgCl2 + H2鈫�
31銆侀摑鍜�
鍙嶅簲锛�2Al + 6HCl === 2AlCl3 + 3H2鈫�
26锛�31鐨勭幇璞★細鏈夋皵娉′骇鐢熴��
32銆侀搧鍜岀█鐩愰吀鍙嶅簲锛欶e + 2HCl === FeCl2 + H2鈫�
33銆侀搧鍜岀█纭�閰稿弽搴旓細Fe + H2SO4 === FeSO4 + H2鈫�
32锛�33鐨勭幇璞★細鏈夋皵娉′骇鐢燂紝婧舵恫鐢辨棤鑹插彉鎴愭祬缁胯壊銆�
锛�2锛夐噾灞炲崟璐� + 鐩愶紙婧舵恫锛� ---鍙︿竴绉嶉噾灞� + 鍙︿竴绉嶇洂
36銆侀搧涓�
鍙嶅簲锛欶e+CuSO4==Cu+FeSO4
鐜拌薄锛氶搧鏉¤〃闈㈣�嗙洊涓�灞傜孩鑹查�楁彙鐨勭墿璐�锛屾憾娑茬敱钃濊壊鍙樻垚娴呯豢鑹层��
(鍙や唬婀挎硶鍒堕摐鍙娾��
寰楅搧鍒欏寲閾溾�濇寚鐨勬槸姝ゅ弽搴�)
40銆侀攲鐗囨斁鍏�
婧舵恫涓�锛欳uSO4+Zn==ZnSO4+Cu
鐜拌薄锛氶攲鐗囪〃闈㈣�嗙洊涓�灞傜孩鑹茬殑鐗╄川锛屾憾娑茬敱钃濊壊鍙樻垚鏃犺壊銆�
41銆侀摐鐗囨斁鍏�
涓�锛�2AgNO3+Cu==Cu(NO3)2+2Ag
鐜拌薄锛氶摐鐗囪〃闈㈣�嗙洊涓�灞傞摱鐧借壊鐨勭墿璐�锛屾憾娑茬敱鏃犺壊鍙樻垚钃濊壊銆�
锛�3锛�
锛�
鎴栨阿姘斺啋閲戝睘锛嬩簩姘у寲纰虫垨姘�
38銆�
杩樺師
锛�3C+ 2Fe2O3 楂樻俯 4Fe + 3CO2鈫�
39銆�
杩樺師
锛欳+ 2CuO 楂樻俯 2Cu + CO2鈫�
鐜拌薄锛氶粦鑹茬矇鏈�鍙樻垚绾㈣壊锛屾緞娓�
鍙樻祽娴娿��
25銆佹阿姘旇繕鍘�
锛欻2 + CuO 鈻� Cu + H2O
鐜拌薄锛氶粦鑹茬矇鏈�鍙樻垚绾㈣壊锛岃瘯绠″唴澹佹湁姘寸彔鐢熸垚
34銆侀晛鍜�
鍙嶅簲锛歁g+CuO Cu+MgO
35銆佹阿姘斾笌
鍙嶅簲锛欶e2O3+3H2 2Fe+3H2O
37銆�
閫氳繃鐏肩儹纰冲眰锛欻2O + C 楂樻俯 H2 + CO
鍥涖��
锛�
1銆�
锛嬮吀鈫掔洂锛婬2O
Fe2O3+6HCl==2FeCl3+3H2O Fe2O3+3H2SO4==Fe2(SO4)3+3H2O
CuO+H2SO4==CuSO4+H2O ZnO+2HNO3==Zn(NO3)3+H2O
2銆佺⒈锛嬮吀鈫掔洂锛婬2O
Cu(OH)2+2HCl==CuCl2+2H2O Cu(OH)2+H2SO4==CuSO4+2H2O
NaOH+HCl==NaCl+H2O 2NaOH+H2SO4==Na2SO4+2H2O
NaOH+HNO3==NaNO3+H2O Mg(OH)2+2HNO3==Mg(NO3)2+2H2O
Ba(OH)2+H2SO4==BaSO4鈫�+2H2O
3銆侀吀锛嬬洂鈫掓柊鐩愶紜鏂伴吀
CaCO3+2HCl==CaCl2+H2O+CO2鈫� Na2CO3+2HCl==2NaCl+H2O+CO2鈫�
HCl+AgNO3==AgCl鈫�+HNO3 H2SO4+BaCl2==BaSO4鈫�+2HCl
Ba(NO3)2+H2SO4==BaSO4鈫�+2HNO3 NaHCO3+HCl==NaCl+H2O+CO2鈫�
4銆佺洂1锛嬬洂2鈫掓柊鐩�1锛嬫柊鐩�2
KCl+AgNO3==AgCl鈫�+KNO3 NaCl+AgNO3==AgCl鈫�+NaNO3
Na2SO4+BaCl2==BaSO4鈫�+2NaCl BaCl2+2AgNO3==2AgCl鈫�+Ba(NO3)2
5銆佺洂锛嬬⒈鈫掓柊鐩愶紜鏂扮⒈
CuSO4+2NaOH==Cu(OH)2鈫�+Na2SO4 FeCl3+3NaOH==Fe(OH)3鈫�+3NaCl
Ca(OH)2+Na2CO3==CaCO3鈫�+2NaOH NaOH+NH4Cl==NaCl+NH3鈫�+H2O
浜斻�佸叾瀹冨弽搴旓細
1銆佷簩姘у寲纰抽�氬叆婢勬竻
锛�
CO2 +Ca(OH)2 ==CaCO3鈫�+ H20鐜拌薄锛氭緞娓�
鍙樻祽娴娿��
锛堢敤婢勬竻鐭崇伆姘村彲浠ユ��楠孋O2锛屼篃鍙�浠ョ敤CO2妫�楠岀煶鐏版按锛�
2銆�
鍜�
鍙嶅簲锛歋O2 +Ca(OH)2 ==
+ H20
3銆�
鍜�
鍙嶅簲锛歋O3 +Ca(OH)2 ==CaSO4+ H20
4銆�
鍜屼簩姘у寲纰冲弽搴旓紙闄ゅ幓浜屾哀鍖栫⒊锛夛細2NaOH + CO2 ==== Na2CO3 + H2O
5銆�
鍜�
鍙嶅簲锛堥櫎鍘�
锛夛細2NaOH + SO2 ==== Na2SO3 + H2O
6銆�
鍜�
鍙嶅簲锛堥櫎鍘�
锛夛細2NaOH + SO3 ==== Na2SO4 + H2O
娉ㄦ剰锛�1锛�6閮芥槸锛�
+纰� -------- 鐩� + 姘�
7銆佺敳鐑峰湪绌烘皵涓�鐕冪儳锛欳H4 + 2O2 鐐圭噧 CO2 + 2H2O
鐜拌薄锛氬彂鍑烘槑浜�鐨勮摑鑹茬伀鐒帮紝
鍐呭�佹湁姘寸彔锛屾緞娓呯煶鐏版按鍙樻祽娴娿��
8銆侀厭绮惧湪绌烘皵涓�鐕冪儳锛欳2H5OH + 3O2 鐐圭噧 2CO2 + 3H2O
鐜拌薄锛氬彂鍑鸿摑鑹茬伀鐒帮紝
鍐呭�佹湁姘寸彔锛屾緞娓呯煶鐏版按鍙樻祽娴娿��
9銆�
锛欳O+ CuO 鍔犵儹 Cu + CO2
鐜拌薄锛氶粦鑹茬矇鏈�鍙樻垚绾㈣壊锛屾緞娓呯煶鐏版按鍙樻祽娴娿��
10銆�
杩樺師
锛�3CO+ Fe2O3 楂樻俯 2Fe + 3CO2
鐜拌薄锛氱孩鑹茬矇鏈�鍙樻垚榛戣壊锛屾緞娓呯煶鐏版按鍙樻祽娴娿�傦紙鍐剁偧閾佺殑涓昏�佸弽搴斿師鐞嗭級
11銆�
杩樺師
锛欶eO+CO楂樻俯Fe+CO2
12銆佷竴姘у寲纰宠繕鍘�
锛欶e3O4+4CO楂樻俯3Fe+4CO2
13銆�
锛�6CO2 + 6H2O鍏夌収
+6O2
14銆�
鐨勬哀鍖栵細
+6O2 6CO2 + 6H2O
涔濆勾鍏ㄩ儴锛�
鍒舵哀姘旂殑鍙嶅簲
1锛庣敤杩囨哀鍖栨阿鍒舵哀姘�2H2O2 浜屾哀鍖栭敯 2H2O+O2鈫�
2锛庣敤楂橀敯閰搁捑鍒舵哀姘�2KMnO4 鍔犵儹 K2MnO4+MnO2+O2鈫�
3.鐢ㄦ隘閰搁捑鍒跺彇姘ф皵 2KClO3鍔犵儹3KCl+3O2
鐗╄川涓庢哀姘旂殑鍙嶅簲
3锛庨摑鍦ㄦ哀姘斾腑鐕冪儳4Al+3O2鐐圭噧2Al2O3
4锛庨搧鍦ㄦ哀姘斾腑鐕冪儳3Fe+2O2鐐圭噧Fe3O4
5锛庣⒊鐕冪儳C + O2 鐐圭噧CO2
6锛庨晛鐕冪儳 2Mg+O2鐐圭噧2MgO
7锛庣～鐕冪儳S + O2 鐐圭噧SO2
8锛庣孩纾锋垨鐧界７鍦ㄧ噧鐑�/鍙戜护鏋�浜х敓鐧界儫
4P + 5O2 鐐圭噧2P2O5
9锛庣⒊涓嶅厖鍒嗙噧鐑�2C+O2 鐐圭噧 2CO
10锛庡ぉ鐒舵皵銆佹布姘旓紙涓昏�佹垚鍒嗙敳鐑稢H4锛夌敤浣滅噧鏂機H4+2O2鐐圭噧2H2O+CO2
11锛庨厭绮撅紙涔欓唶锛夌噧鐑� C2H5OH +3O2鐐圭噧3H2O+2CO2
12锛庢阿姘斾綔鐕冩枡 2H2+O2 鐐圭噧2H2O
13锛庝竴姘у寲纰筹紙鐓ゆ皵涓昏�佹垚鍒嗭級鐕冪儳 2CO+O2鐐圭噧2CO2
14锛庣數瑙ｆ按2H2O閫氱數2H2鈫�+O2鈫�
15锛庡疄楠屽�ゅ埗鍙栦簩姘у寲纰�/鐢ㄥぇ鐞嗙煶鎴栫煶鐏扮煶涓庣█鐩愰吀鍙嶅簲鍒跺彇浜屾哀鍖栫⒊/鐢ㄧ洂閰搁櫎姘村灑/鐢ㄥⅷ楸奸�ㄧ矇闄よ儍閰歌繃澶�/鐢ㄧ洂閰告��楠屽ぇ鐞嗙煶銆佺煶鐏扮煶鎴栬礉澹充腑鍚�鏈夌⒊閰搁挋
CaCO3+2HCl=CaCl2+H2O+CO2鈫�
浜屾哀鍖栫⒊鍙備笌鐨勫弽搴�
16锛庝簩姘у寲纰抽�氬叆婢勬竻鐭崇伆姘翠腑/浜屾哀鍖栫⒊涓庣煶鐏版按鍙嶅簲/鐢ㄧ煶鐏版按妫�楠屼簩姘у寲纰�/鐭崇伆姘村湪绌烘皵涓�鍙樿川/鐢ㄧ煶鐏版祮绮夊埛澧欏��
CO2 +Ca(OH)2 = CaCO3鈫�+ H2O
17锛庝簩姘у寲纰充笌姘㈡哀鍖栭挔鍙嶅簲/姘㈡哀鍖栭挔鍦ㄧ┖姘斾腑鍙樿川
CO2+2NaOH = Na2CO3+ H2O
18锛庝簩姘у寲纰充笌姘村弽搴�/纰抽吀楗�鏂欎腑鍙嶅簲CO2 + H2O = H2CO3
纰抽吀涓嶇ǔ瀹氬垎瑙�H2CO3 = CO2鈫� + H2O
19锛庝簩姘у寲纰抽�氳繃鐐界儹鐨勭⒊C + CO2楂樻俯2CO
涓�姘у寲纰冲弬涓庣殑鍙嶅簲
20锛庝竴姘у寲纰宠繕鍘熸哀鍖栭摐锛堜竴姘у寲纰冲叿鏈夎繕鍘熸�э級CO+ CuO螖 Cu+ H2O
21锛庝竴姘у寲纰宠繕鍘熸哀鍖栭搧锛堢偧閾侊級Fe2O3+3CO楂樻俯鑼勬墥 2Fe+3CO2
涓�姘у寲纰崇噧鐑э紙涓�姘у寲纰冲叿鏈夊彲鐕冩�э級2CO+O2鐐圭噧2CO2
纰冲弬涓庣殑鍙嶅簲
22锛庢湪鐐�锛堢⒊锛夎繕鍘熸哀鍖栭摐锛堣繕鍘熸�э級C+2CuO楂樻俯 2 Cu +CO2 鈫�
纰崇噧鐑э紙鍙�鐕冭斀绾冲垽鎬э級C + O2 鐐圭噧CO2 2C+O2 鐐圭噧 2CO
23锛庢阿姘旇繕鍘熸哀鍖栭摐锛堟阿姘旂殑杩樺師鎬э級H2+ CuO螖 Cu+ H2O
24锛庨吀闆ㄧ殑褰㈡垚/浜屾哀鍖栫～涓庢按鍙嶅簲鐢熸垚浜氱～閰窼O2 + H2O = H2SO3
閲戝睘鍙備笌鐨勫弽搴�
25锛庨噾灞烇紙涓昏�丮g Al Zn Fe锛変笌閰革紙绋�鐩愰吀鎴栫█纭�閰革級鍙嶅簲
Fe+2HCl =FeCl2+H2鈫� Fe+H2SO4=FeSO4+H2鈫�
2Al+6HCl=2AlCl3+3H2鈫� 2Al+3H2SO4=Al2(SO4)3+3H2鈫�
Zn+2HCl=ZnCl2+H2鈫� Zn+H2SO4=ZnSO4+H2鈫�
Mg+2HCl =MgCl2+H2鈫� Mg+H2SO4 =MgSO4+H2鈫�
26锛庨噾灞炰笌鐩愭憾娑插弽搴�
閾佷笌纭�閰搁摐鍙嶅簲/瀹忔敼婀挎硶鐐奸摐/鐢ㄩ搧妫�楠屾垨闄ゅ幓宸ヤ笟搴熸按涓�閾滅�诲瓙
Fe+CuSO4=Cu+FeSO4
姘㈡哀鍖栭挔銆佹阿姘у寲閽欏弬涓庣殑鍙嶅簲
27锛庯紙1锛夌⒈涓庨潪閲戝睘姘у寲鐗╁弽搴旓細
浜屾哀鍖栫⒊涓庣煶鐏版按鍙嶅簲/鐢ㄧ煶鐏版按妫�楠屼簩姘у寲纰�/鐭崇伆姘村湪绌烘皵涓�鍙樿川/鐢ㄧ煶鐏版祮绮夊埛澧欏�丆O2+Ca(OH)2 = CaCO3鈫�+ H2O
浜屾哀鍖栫⒊涓庢阿姘у寲閽犲弽搴�/姘㈡哀鍖栭挔鍦ㄧ┖姘斾腑鍙樿川 CO2+2NaOH = Na2CO3+ H2O
锛�2锛夌⒈涓庢煇浜涚洂鍙嶅簲锛氱⒊閰搁挔涓庣煶鐏版按鍙嶅簲/鏈夌煶鐏版按妫�楠岀⒊閰搁挔/鐢ㄧ煶鐏扮煶涓庣⒊閰搁挔涓哄師鏂欏埗鍙栨阿姘у寲閽燦a2CO3+ Ca(OH)2 = CaCO3鈫�+2NaOH
29锛庣厖鐑х煶鐏扮煶/宸ヤ笟涓婄敤鐭崇伆鐭冲埗鍙栫敓鐭崇伆 CaCO3 楂樻俯 CaO+ CO2鈫�
30锛庢哀鍖栭挋涓庢按鍙嶅簲/鐢ㄧ敓鐭崇伆鍋氬共鐕ュ墏/鐢ㄧ敓鐭崇伆鍒跺彇鐔熺煶鐏版垨鐭崇伆姘�
CaO+ H2O = Ca(OH)2
瀹為獙瀹ょ敤閿屼笌绋�纭�閰稿弽搴斿埗鍙栨阿姘� Zn+H2SO4=ZnSO4+H2鈫�
